KSEEB SSLC Class 10 Maths Solutions Chapter 13 Statistics Ex 13.4

KSEEB SSLC Class 10 Maths Solutions Chapter 13 Statistics Ex 13.4 Karnataka SSLC Class 10 Maths Solutions Chapter 13 Statistics Exercise 13.4 Question 1. The following distribution gives the dialy income of 50 workers of a factory. Convert the distribution above to a less than type cumulative frequency distribution, and draw its ogive. Solution: n … Read more

KSEEB SSLC Class 10 Maths Solutions Chapter 13 Statistics Ex 13.3

KSEEB SSLC Class 10 Maths Solutions Chapter 13 Statistics Ex 13.3 Karnataka SSLC Class 10 Maths Solutions Chapter 13 Statistics Exercise 13.3 Question 1. The following frequency distribution gives the monthly consumption of electricity of 68 consumers of a locality. Find the median, mean and mode of the data and compare them. Solution: (i) n … Read more

KSEEB SSLC Class 10 Maths Solutions Chapter 13 Statistics Ex 13.2

KSEEB SSLC Class 10 Maths Solutions Chapter 13 Statistics Ex 13.2 Karnataka SSLC Class 10 Maths Solutions Chapter 13 Statistics Exercise 13.2 Question 1. The following table shows the ages of the patients admitted in a hospital during a year : Find the mode and the mean of the data given above. Compare and interpret … Read more

KSEEB SSLC Class 10 Maths Solutions Chapter 13 Statistics Ex 13.1

KSEEB SSLC Class 10 Maths Solutions Chapter 13 Statistics Ex 13.1 Karnataka SSLC Class 10 Maths Solutions Chapter 13 Statistics Exercise 13.1 Question 1. A survey was conducted by a group of students as a part of their environment awareness programme, in which they collected the following data regarding the number of plants in 20 … Read more

KSEEB Solutions for Class 10 Maths Chapter 12 Some Applications of Trigonometry Additional Questions

KSEEB Solutions for Class 10 Maths Chapter 12 Some Applications of Trigonometry Additional Questions Karnataka State Syllabus Class 10 Maths Chapter 12 Some Applications of Trigonometry Additional Questions I. Multiple Choice Questions: Question 1. The angle of elevation of the top of a tower from a point at a distance of 100 m from the … Read more

KSEEB SSLC Class 10 Maths Solutions Chapter 12 Some Applications of Trigonometry Ex 12.1

KSEEB SSLC Class 10 Maths Solutions Chapter 12 Some Applications of Trigonometry Ex 12.1 Karnataka SSLC Class 10 Maths Solutions Chapter 12 Some Applications of Trigonometry Exercise 12.1 Question 1. A circus artist is climbing a 20 m long rope, which is tightly stretched and tied from the top of a vertical pole to the … Read more

KSEEB Solutions for Class 10 Maths Chapter 11 Introduction to Trigonometry Additional Questions

KSEEB Solutions for Class 10 Maths Chapter 11 Introduction to Trigonometry Additional Questions Karnataka State Syllabus Class 10 Maths Chapter 11 Introduction to Trigonometry Additional Questions I. Multiple Choice Questions: Question 1. How many faces does a coin has a. 1 b. 2 c. 3 d. 4 Answer: b. 2   Question 2. How many … Read more

KSEEB SSLC Class 10 Maths Solutions Chapter 11 Introduction to Trigonometry Ex 11.4

KSEEB SSLC Class 10 Maths Solutions Chapter 11 Introduction to Trigonometry Ex 11.4 Karnataka SSLC Class 10 Maths Solutions Chapter 11 Introduction to Trigonometry Exercise 11.4 Question 1. Express the trigonometric ratios sin A, sec A and tan A in terms of cot A. Solution: cosec2 A – cot2 A = 1 cosec2 A = 1 + cot2 A … Read more

KSEEB SSLC Class 10 Maths Solutions Chapter 11 Introduction to Trigonometry Ex 11.3

KSEEB SSLC Class 10 Maths Solutions Chapter 11 Introduction to Trigonometry Ex 11.3 Karnataka SSLC Class 10 Maths Solutions Chapter 11 Introduction to Trigonometry Exercise 11.3 Question 1. Evaluate : iii) cos 48° – sin 42° iv) cosec 31° – sec 59° Solution:   Question 2. Show that i) tan 48° tan 23° tan 42° … Read more

KSEEB SSLC Class 10 Maths Solutions Chapter 11 Introduction to Trigonometry Ex 11.2

KSEEB SSLC Class 10 Maths Solutions Chapter 11 Introduction to Trigonometry Ex 11.2 Karnataka SSLC Class 10 Maths Solutions Chapter 11 Introduction to Trigonometry Exercise 11.2 Question 1. Evaluate the following : i) sin 60° cos 30° + sin 30° cos 60° ii) 2 tan2 45° + cos2 30° – sin2 60° Solution: i) sin 60° cos … Read more