KSEEB Solutions for Class 7 Maths Chapter 6 The Triangles and Its Properties Ex 6.5 Karnataka State Syllabus Class 7 Maths Chapter 6 The Triangles and Its Properties Ex 6.5 Question 1. PQR is a triangle, right-angled at P. If PQ = 10cm and PR = 24 cm, find QR. Solution: PQR is a right … Read more
KSEEB Solutions for Class 7 Maths Chapter 6 The Triangles and Its Properties Ex 6.4 Karnataka State Syllabus Class 7 Maths Chapter 6 The Triangles and Its Properties Ex 6.4 Question 1. Is it possible to have a triangle with the following sides ? i) 2 cm, 3 cm, 5 cm. Solution: greatest side is … Read more
KSEEB Solutions for Class 7 Maths Chapter 6 The Triangles and Its Properties Ex 6.3 Karnataka State Syllabus Class 7 Maths Chapter 6 The Triangles and Its Properties Ex 6.3 Question 1. Find the value of the unknown x in the following diagrams : Solution: i) ∠A + ∠B + ∠C = 180° x° + … Read more
KSEEB Solutions for Class 7 Maths Chapter 6 The Triangles and Its Properties Ex 6.2 Karnataka State Syllabus Class 7 Maths Chapter 6 The Triangles and Its Properties Ex 6.2 Question 1. Find the value of the unknown exterior angle x in the following diagrams : i) ∠x = 50° + 70° = 120° (∵ … Read more
KSEEB Solutions for Class 7 Maths Chapter 6 The Triangles and Its Properties Ex 6.1 Karnataka State Syllabus Class 7 Maths Chapter 6 The Triangles and Its Properties Ex 6.1 Question 1. In the ∆PQR PQ = PR PM is the Median (∵ QM = MR) PM is the altitude. (∵ PMR = 90°) ∴ … Read more
KSEEB Solutions for Class 7 Maths Chapter 5 Lines and Angles Ex 5.2 Karnataka State Syllabus Class 7 Maths Chapter 5 Lines and Angles Ex 5.2 Question 1. State the property that is used in each of the following statements ? i) If a || b, then ∠1 = ∠5 Solution: The two parallel lines … Read more
KSEEB Solutions for Class 7 Maths Chapter 5 Lines and Angles Ex 5.1 Karnataka State Syllabus Class 7 Maths Chapter 5 Lines and Angles Ex 5.1 Question 1. Find the complement of each of the following angles : i) The complement of 70° Solution: The complement of the angle 20° = 90° – 20° = … Read more
KSEEB Solutions for Class 7 Maths Chapter 4 Simple Equations Ex 4.4 Karnataka State Syllabus Class 7 Maths Chapter 4 Simple Equations Ex 4.4 Question 1. Set up equations and solve them to find the unknown numbers in the following cases : a) Add 4 to eight times a number; you get 60. Solution: Let … Read more
KSEEB Solutions for Class 7 Maths Chapter 4 Simple Equations Ex 4.3 Karnataka State Syllabus Class 7 Maths Chapter 4 Simple Equations Ex 4.3 Question 1. Solve the following equations : Solution: Substitute the value of y = 8 in the given equation ∴ LHS = RHS (verified) b) 5t + 28 = 10 Solution: … Read more
KSEEB Solutions for Class 7 Maths Chapter 4 Simple Equations Ex 4.2 Karnataka State Syllabus Class 7 Maths Chapter 4 Simple Equations Ex 4.2 Question 1. Given first the step you will use to separate the variable and then solve the equation: a) x – 1 = 0 Solution: The given equation = x – … Read more