Kerala Syllabus 10th Standard Chemistry Solutions Chapter 1 Periodic Table and Electronic Configuration
Kerala Syllabus 10th Standard Chemistry Solutions Chapter 1 Periodic Table and Electronic Configuration
Kerala State Syllabus 10th Standard Chemistry Solutions Chapter 1 Periodic Table and Electronic Configuration
Periodic Table and Electronic Configuration Text Book Questions and Answers
Kerala Syllabus 10th Standard Chemistry Chapter 1 Text Book Page No: 7
→ What is the basis of classification of elements in the periodic table?
Answer:
Atomic Number
Sslc Chemistry Chapter 1 Questions And Answers Text Book Page No: 8
→ Atomic number of sodium is 11 Electronic configuration – 2,8,1
GroupNumber — …………..
Period number — …………
Answer:
Group Number — 1
Period number — 3
→ Is the group 1 element a metal or a nonmetal?
Answer:
Metal
→ Write the electronic configuration of sodium and argon and complete the Table.
Answer:
Periodic Table And Electronic Configuration Class 10 Notes Text Book Page No: 9
→ How many electrons are present in the M shell, the outermost shell of argon?
Answer:
8
→ What is the maximum number of electrons that can be accommodated in the M Shell?
Answer:
18
→ The ‘K’ shell, which is the first shell, has 1 subshell. The next ‘L’ shell has 2, and so on. What will be the number of subshells in the ‘M’ shell and ‘N’
M = ……………… , N = ……………….
Answer:
M = 3, N = 4
→ Which subshell is common to all shells?
Answer:
S
Sslc Chemistry Chapter 1 Notes Kerala Syllabus Text Book Page No: 10
→ Complete the Table 1.3
Answer:
→ Complete the Table 1.4
Answer:
→ What is the maximum number of electronics that can be accommodated in the ‘s’?
Answer:
2
→ What may be the maximum number of electrons to be filled in the ‘p’ subshell?
Answer:
6
Periodic Table And Electronic Configuration Class 10 Text Book Page No: 11.
The atomic number of hydrogen is 1(1H)
→ How many electrons are present?
Answer:
1
→ In which shell is the electron filled?
Answer:
‘K’ shell
→ In which subshell?
Answer:
S
→ How many electrons are present in helium (2He)?
Answer:
2
Chemistry Class 10 Chapter 1 Kerala Syllabus Text Book Page No: 12
→ Complete the subshell electronic configuration?
Answer:
1s2
→ Write the electronic configuration of Lithium (3Li)
Answer:
1s2 2s1
→ Complete the electronic configuration of beryllium?
Answer:
Be[Z=4] -1s2 2s2
→ Write the electronic configuration of Boron
Answer:
B[Z=5] -1s1 2s2 2p1
→ Write the electronic configuration of Carbon
Answer:
C[Z=6] – 1s2 2s2 2p2
→ Complete the Table 1.6
Answer:
Class 10 Chemistry Chapter 1 Periodic Table And Electronic Configuration Text Book Page No: 13
→ How was the shell wise electronic configuration of potassium written?
Answer:
2, 8, 8, 1
→ Compare the energies of Is and 2s subshells. Which one has lower energy?
Answer:
1s < 2s
Sslc Chemistry Notes Chapter 1 Kerala Syllabus Question 14.
Among the 3s & 3p subshells which has higher energy?
Answer:
3s < 3p
→Among the 3d & 4s subshells which has higher energy?
Answer:
4s < 3d
→ Write down the subshells in the increasing order of their energies.
Answer:
1s <2s <2p <3s <3p <4s <3d <4p
→ Write the subshell wise electronic configu-ration of potassium.
Answer:
1s2 2s2 2p6 3s2 3p6 4s2
→The electronic configuration of scandium (2lSc) is
Answer:
s2 2s2 2p6 3s2 3p6 3d1 4s2
Periodic Table And Electronic Configuration Kerala Syllabus Text Book Page No: 14
→ Write the electronic configu ration of 22Ti, 23V, the two elements after Sc.
Answer:
22Ti — 1s2 2s2 2p6 3s2 3p6 3d2 4s2
23V — 1s2 2s2 2p6 3s2 3p6 3d3 4s2
→Which is the noble gas preceding sodium (11Na)?
Answer:
Neon(Ne)
→ Write its subshell electronic configuration.
Answer:
10Ne – 1s2 2s2 2p6
→ Subshell electronic configuration of sodium?
Answer:
11Na – 1s2 2s2 2p6 3s1
Periodic Table And Electronic Configuration Class 10 Important Questions Text Book Page No: 15
→ Using the symbol of neon, write the subshell electronic configuration of sodium?
Answer:
[Ne] 3s1
→ Complete the Table 1.7
Answer:
→ Write the subshell electronic configuration of 24Cr
Answer:
24Cr – 1s2 2s2 2p6 3s2 3p6 3d5 4s1
→ On the basis of this, identify the correct electronic configuration of 29Cu from those given below:
Answer:
1s2 2s2 2p6 3s2 3p6 3d9 4s2 – False
1s2 2s2 2p6 3s2 3p6 3d10 4s1 – True
Periodic Table And Electronic Configuration Class 10 Question Paper Text Book Page No: 16
If the subshell wise electronic configuration of an atom is 1s2 2s2 2p6 3s2, find answers to the following:
→ How many shells are present in this atom?
Answer:
3
→Which are the subshells of each shell?
Answer:
K — Is, L — 2s, 2p, M — 3s
→Which is the subshell to which the last electron was added?
Answer:
3s
→ What is the total number of electrons in the atom?
Answer:
12
→ What is its atomic number?
Answer:
12
→ How can the subshell electronic configuration be written in a short form?
Answer:
[Ne]3s2
Periodic Table And Electronic Configuration Class 10 Questions And Answers Text Book Page No: 17
→ Complete the Table 1.8
→ Which is the subshell of lithium to which the last electron was added?
Answer:
S
→ What about the subshell to which the last electron of nitrogen was added
Answer:
p
→ What is the relation between the subshell to which the last electron was added and the block to which the element belongs?
Answer:
The subshell in which the last electron enters represent the block in which the element belongs.
→ Write the subshell electronic configuration of the following elements and find the blocks to which they belong.
a. 4Be: ………………..
b. 26Fe……………..
c. 18Ar: ……………
Answer:
a. 4Be : 1s2 2s2 — s block
b. 26Fe : Is2 2s2 2p6 3s2 3p6 3d6 4s2 — d block
c. 18Ar : 1s2 2s2 2p6 3s2 3p6 — p block
Text Book Page No: 18
→ Complete the Table 1.9
→ Complete the Table 1.10
→ What is the relation between number of electrons present in the last ‘s’ subshell and their group number?
Answer:
The number of electrons in the outermost ‘s’
subshell = The group number
Text Book Page No: 20
→ When the s block elements react, do they donate or accept electrons?
Answer:
They donate electrons.
→ Which type of chemical bond is usually formed?
Answer:
Ionic bonds
→ How many electrons are donated by the first group elements in chemical reactions ?-
Answer:
One
→ How many electrons are donated by the second group elements in chemical reaction?
Answer:
Two
→ Complete the table 1.11
→ ‘s’ block elements are present at the extreme left side of the periodic table. Relating to their position, what other characteristics can be listed out?
Answer:
- More metallic character s
- Less ionization energy
- Less electronegativity
- Lose of electrons in chemical reaction
- Compounds are mostly ionic
- Oxides and hydroxides are basic in nature
Text Book Page No: 21
→ Which are the group included in the p block
Answer:
13, 14, 15, 16, 17, 18
→ In which subshell did the filling of the last electron take place?
Answer:
p subshell
→ Complete the table 1.13.
Text Book Page No: 22
The outermost subshell wise electronic configuration of an element Y (Symbol is hot real) is 3s2 3p4.
→ To which period and group does this element belongs to?
Answer:
Period = 3, Group = 16
→ Write down the outermost subshell electronic configuration of the element coming just below it in the same group?
Answer:
1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p4
→ Find out examples of elements in such different states with the help of the periodic tables?
Answer:
Solid – Li, Be, B, C, Na, Mg, Al, Si
Liquid – Br
Gas – H, He, N, O, F, Ne
→ Which element has the highest ionization energy in each period?
Answer:
Group 18 elements.
Text Book Page No: 23
→ The elements having the highest electronegativity is in the p block. Find its name and position?
Answer:
Fluorine F, Period – 2, p block, Group 17
→ Analyze the general characteristics of the p block elements and prepare a note on this?
Answer:
- The outermost p subshell of the p block elements contains 1 to 6 electrons.
- Elements showing positive oxidation state and negative oxidation state are members of this block.
- There are metals and nonmetals in these blocks.
- Elements in the solid, liquid and gaseous states are present in p block.
→ Complete the table 1.14
→ Which element has a valency 1?
Answer:
Y
→Which element shows metallic character?
Answer:
X
→ Which element has the highest ionization energy?
Answer:
Y
→ Write the chemical formula of the compound formed by the combination of X and Y and label the oxidation states?
Answer:
Compound: X Y2
Oxidation state: X2+, Y1-
→ Where is the position of d block elements in the periodic table?
Answer:
3rd Group to 12th Group
→ From which period onwards does the d block begin?
Answer:
4
Text Book Page No: 24
→ Put a tick mark ✓’ against the statements below, which are applicable to d block elements.
Answer:
1. ‘✓’ These are metals.
2. ‘✓’ The last electron is filled in the penultimate shell.
3. ‘✗’ In the case of these elements in the 4th period, the last electron is filled in 4s.
4. ‘✓’ These are found in groups 3 to 12 of the periodic table.
Text Book Page No: 25
→ Complete the table 1.16
→ How does Fe change to Fe2+?
Answer:
By losing 2 electrons from 4s valence subshell.
Text Book Page No: 26
→ Write down the subshell electronic configuration of Fe21.
Answer:
1s2 2s2 2p6 3s2 3p6 3d6
There is only a small difference of energy between the outermost s subshell and the penultimate d subshell of transition elements.
→ If so, which will be the subshell from which iron loses the third electron?
Answer:
From 3d sub-shell
→ Write the electronic configuration of Fe3+ on the basis of this.
Answer:
1s2 2s2 2p6 3s2 3p6 3d5
→ Write the subshell electronic configuration of Manganese (Mn).
Answer:
1s2 2s2 2p6 3s2 3p6 3d5 4s2
→ Complete the table 1.17
Answer:
Text Book Page No: 27
→ Examine these compounds available. Find more colored compounds and extend the list.
Answer:
- Copper sulfate CuSO4.5H2O – blue,
- Copper nitrate Cu(NO3)2.6H2O – pink.
- Potassium permanganate KMnO4 – violet.
- Ferrous sulfate FeSO4.7H2O – Green,
- Ferrous nitrate (Fe(NO3)2.6H2O) – light green
Text Book Page No: 28
→ List out the dements of the s block?
Answer:
A, B
→ Which elements shows+2 oxidation state?
Answer:
B, C, D
→ Which elements contains 5 electrons in the outermost shell?
Answer:
E
→ Which is the element that has 5 p electrons in the outermost shell?
Answer:
G
→ Which are the elements in which the last electron enters the d subshell?
Answer:
C, D
→ Which element has the highest ionization energy?
Answer:
H
→ Which is the highly reactive nonmetal?
Answer:
G
→ Which elements show -2 oxidation state?
Answer:
F
Text Book Page No: 29
The outermost electron configuration of an element in this is 2s2 2p6
→ Which is the element?
Answer:
H
→ Write down the complete subshell electronic configuration?
Answer:
Is2 2s2 2p6
→ Write any two characteristics of this element?
Answer:
- Noble element / gases.
- The outermost shell is completely filled
→ Write the chemical number of questions, the answer of which is an element in the table
Answer:
A G
Periodic Table and Electronic Configuration Let Us Assess
Question 1.
Based on the hints given, find out the atomic number and write down the subshell electronic configuration of elements (Symbols used are not real).
i. A – period 3 group 17
ii. B – period 4 group 6
Answer:
A17 — 1s2 2s2 2p6 3s2 3p5
B24 — 1S2 2s2 2p6 3S2 3p6 3d5 4S1
Question 2.
When the last electron of an atom was filled in the 3d subshell, the subshell electronic configuration was recorded as 3d8 Answer the questions related to this atom.
1. Complete subshell electronic configuration
2. Atomic number
3. Block
4. Period number
5. Group number
Answer:
1. Complete subshell electronic configuration:
1 s2, 2s2, 2p6, 3s2, 3p6, 3d8, 4s2
2. Atomic number: 28
3. Block : d
4. Period number: 4
5. Groupnumber : 8 + 2 = 10
Question 3.
Pick out the wrong ones from the subshell electronic configuration given below.
a. 1s2 2s2 2p7
b. 1s2 2s2 2p2
c. 1s2 2s2 2p5 3s2
d. 1s2 2s2 2p6 3s2 3p6 3d2 4s2
e. 1s2 2s2 2p6 3s2 3p6 3d2 4s2
Answer:
Wrong electronic configuration
a. 1s2, 2s2, 2p7
(2p maximum 6 electrons only)
c. 1s2, 2s2, 2p5, 3s1 (electrons are filled in 3s only after filling 6 electrons in 2p)
d. 1s2, 2s2, 2p6, 3s2, 3p6, 3d2, 4s1 (electrons are filled in 3d only after filling 2 electrons in 4s)
Question 4.
The element X in group 17 has 3 shells. If so,
a. Write the subshell electronic configuration of the element.
b. Write the period number,
c. What will be the chemical formula of the compound formed if the element X reacts with element Y of the third period which contains one electron in the p subshell?
Answer:
a. Three shells are K, L, M. The subshells are 1s, 2s, 2p, 3s, 3p, 3d
Group number: 17
Electrons in last shell: 7
Shell electronic configuration: 2,8,7
Sub-shell electronic configuration 1s2, 2s2, 2p6, 3s2, 3p5
b. Period-3
c. Y – Third period
∴ shells – 3
1 electron in p – subshell
Total electrons in valence shell 2+1=3 (2 electrons in s + 1 electron in p)
Valency of x – 1(1 electron is recieved – electro negative atom)
Valency of y – 3 (3 electrons are lost – electro positive atom)
Therefore they combine to form compounds with chemical formula YX3
(Symbol of electropositive element first followed by electro negative element).
Question 5.
The element Cu with atomic number 29 undergoes chemical reaction to formation with oxidation number +2.
a. Write down the subshell electronic configuration of this ion.
b. Can this element show variable valency? Why?
c. Write down the chemical formula of one compound formed when this element reacts with chlorine (17CI).
Answer:
a. 29Cu — 1s2, 2s2, 2p6, 3s2, 3p6, 3d10, 4s1
Cu2+ — 1s2, 2s2, 2p6, 3s2, 3p6, 3d9
b. Yes. One electron can be lost from 4s subshell and can’exist as Cu+ ion, It is a d-block element.
c. Copper react with chlorine to form two compounds Cu+, Cu2+ ions react with chlorine to form CuCl and CuCl2 respectively.
Question 6.
Certain subshells of an atom are given below. 2s, 2d, 3f, 3d, 5s, 3p
a. Which are the subshells that are not possible?
b. Give the reason.
Answer:
a. Not possible sub-shells are 2d, 3f
b. d – subshell is not possible in 2nd shell
f – subshell is not possible in 3rd shell
Periodic Table and Electronic Configuration Extended Activities
Question 1.
Prepare the comprehensive table which indicates the name, symbol, electron configuration, subshell configuration of elements having atomic number 1 to 36?
Answer:
Question 2.
Some information related to the elements of the p bllock in the 17th group of the periodic table are given in the table below. Complete the table and analyze the following questions?
Answer:
a. What is the family names of elements belonging to the 17th group?
Answer:
Halogen
b. What is their common valency?
Answer:
1
c. Which element has the highest electro negativity ?
Answer:
F
d. Which element has the highest ionization energy?
Answer:
F
e. List out the name and chemical formula of the compounds formed by these elements with block elements?
Answer:
- sodium chloride – NaCl
- potassium chloride – KCl
- magnesium chloride- MgCl2
- calcium chloride- CaCl2
- magnesium fluoride- MgF2
- calcium fluoride – Ca F2
- sodium iodide – Nal
- potassium iodide – KI
- potassium bromide – KBr
- potassium fluoride – KF
Periodic Table and Electronic Configuration Orukkam Questions and Answers
Question 1.
Complete the table of details about shells and subshells.
a. No of electrons in KLMN shell.
b. No of electrons in each shell.
c. Which subshell is common to all sub-shells?
d. Write names of subshells in accordance with increasing energy level,
e. Identify the incorrect subshell electronic configuration.
– 1s2
– ls2 2p6
– ls2 2s2 2p6
– 1s2 2s2 2p6 3s2 3p2
Answer:
a, K – 2 ; L – 8 ; M – 18 ; N – 32
c. s- Subshell
d. 1s <2s <2p <3s <3p <4s <3d <4p <5s <4d <5p <6s <4f <5s
e. 1s2 2p6
Question 2.
Atomic number of iron is 26. It exhibits Fe2+, Fe3+ oxidation state. Write the subshell electronic configuration.
Question 3.
Manganese, a d-block element exhibits I different oxidation state. Why?
a. Include chemical formulae of more compounds of manganese in the table, write their ; oxidation state and subshell electronic configuration.
b. Write the oxidation number and subshell electronic configuration K, Cl and O.
Answer:
Manganese shows different oxidation states because in manganese 4s and 3d subshell electrons take part in chemical reactions.
a.
Question 4.
Find out atomic number, group, block period using subshell electronic configuration and then complete the table.
Question 5.
Write down the characteristics of s,d,p, f block elements
Answer:
s-block elements:
Elements in which last electron enters into s-subshell are called s-block elements. It contains group I elements (Alkali metals) and group II elements (Alkaline earth metals).
1st group elements lose one electron during chemical combination. Therefore its oxidation state is +1.
2nd group elements lose two electrons from valence shell during chemical combination and their oxidation state is +2.
The highest shell number in a sub-shell electronic configuration is the period number of that element.
1. Group number characteristics = no.of electrons in valence sub-shell.
2. s block ionization energy & electro negativity decreases downwards.
3. Metallic character & reactivity increases downwards.
4. Lose electrons during chemical combination j and they form ionic compounds.
Their oxides and hydroxides are basic.
Their atomic radii are high in a period.
p-block elements:
- Last electron enters into p-subshell.
- Group 13 -18 elements.
- Highly reactive elements are non-metals – group 17,
- These are elements with positive and negative oxidation state.
Group number of p-block elements = electrons in last p-subshell + 12
d-block elements:
- Last electron enters into penultimate d-subshell
- Known as transition elements.
- Metals
- Shows similarity in group and period.
- Variable oxidation states.
- Form coloured compounds.
Group = electrons in ‘d’-subshdl + electrons in s-subshell.
f-block elements:
- Last electron enters into antepenultimate f sub-shell.
- Contains Lanthanoids and Actinoids.
- Variable oxidation state.
- Most of the Actinoids are radioactive.
- Most of the elements are artificial.
- U, Th, Pu are used in nuclear reactors.
- Some elements are used as catalyst in pet-roleum industry.
Periodic Table and Electronic Configuration Evaluation Questions
Question 1.
Write down subshell electronic configuration of Cu1+ and Cu2+
Answer:
Cu1+ – 1s2 2s2 2p6 3s2 3p6 3d10
Cu2+ – 1s2 2s2 2p6 3s2 3p6 3d9
Question 2.
How many ‘s’ subshell electrons are in 1s2, 2s2, 2p6, 3s2, 3p2
Answer:
6 Electrons
Question 3.
11,17,10 are the atomic number of elements X, Y, and Z.
a. Write down their subshell electronic configuration, group, block, period,
b. Write the molecular formulae of the compound formed when any two of the above elements are combined.
c. Write down the oxidation numbers of the elements in those compounds. Write the subshell electronic configuration of both ions.
Answer:
a.
b. X Y
Question 4.
Element ‘X’ is having atomic number 28, it gives two electrons to element ‘Y’.
a Write down the electronic configuration of ‘X’ and its ion
b. In which block ‘X’ belongs?
c. Write down the characteristics of that block
Answer:
a. X28 – 1s2 2s2 2p6 3s2 3p6 3d8 4s2
X2+– 1s2 2s2 2p6 3s2 3p6 3d8
b. d block Compound
c. 1. It exhibits variable oxidation states
2. Forms colored compounds
3. Last electron enters d subshell
Question 5.
a. Write down the group and period of each element.
b. What are the use of writing electronic configuration this fashion?
Answer:
b. Group and period of the element can be identified easily. In the Same way long electron configuration can be avoided.
Question 6.
24Cr – [Ar] 3d5 4s1
29Cu – [Ar] 3d10 4s1
Why chromium and copper exhibits such electronic configuration ?
Answer:
Half filled and completely filled subshells are most stable. Change in the electronic configuration of 24Cr &, 29Cu is due to .this. The electrons in these elements are arranged in such away to give these elements stability.
Periodic Table and Electronic Configuration SCERT Questions and Answers
Question 1.
The electronic configuration of the elements A, B, C, Dare given below.
A – 1s2 2s2 2p6 3s2 3p4
B – 1s2 2s2 2p6 3s2
C – 1s2 2s2 2p6 3s2 3p5
D – 1s2 2s2 2p6 3s1
a. Which of these elements show +2 oxidation state?
b. Which metal belongs to 17th group?
c. Which is the period number of the element A ? What is the basis of your findings?
d. Which of these elements can form basic Oxides?
Answer:
a. B
b. C
c. Period number: 3, Period number = No.of shells
d. B, D
Question 2.
Two compounds of iron are jpven below.
FeSO4 Fe2(SO4)3
(The oxidation state of sulfate radical is-2)
a. Which ofthese compounds show +2 oxidation state for Fe?
b. Which compounds has Fe3+ ion?
c. Write the subshell electronic configuration of Fe3+ ion.
d. Why do transition elements show variable oxidation states?
Answer:
a., FeSO4
b. Fe2(SO4)3
c. Fe3+ – 1s2 2s2 2p6 3s2 3p6 3d5
d. The energy difference between the outer most ‘s’ subshell and penultinate ‘d’ subshell is very small. Hence under suitable conditions, the electrons in ‘d’ subshell also take part in chemical reaction.
Question 3.
Identify the incorrect electronic configurations and correct them.
i) 1s2 2s2 2p3
ii) 1s2 2s2 2p6 3s1
iii) 1s2 2s2 2p6 2d7
iv) 1s2 2s2 2p6 3s2 3p6 3d4
Answer:
iii). 1s2 2s2 2p6 3s2 3p5 .
iv). 1s2 2s2 2p6 3s2 3p6 4s2 3d2
Question 4.
Complete the table.
Answer:
a. – 2
b. 1
c. 17,
d. – 1
e. 12
f. +12
Question 5.
a. Two compounds XY2, XZ4 are given. The oxidation state of Z is 1. What will be the oxidation state of Y ?
b. Write the molecular formula of the compound formed by Y when it combines with aluminum (Al) having oxidation state +3.
Answer:
a. Y= – 2 (oxidation state of X is +4)
b. Al2 Y3
Question 6.
Pick out the statements which suit to f-block elements.
a. All of them are naturally occurring elements.
b. Uranium and Thorium are f block elements.
c. Last electrons is filled in the shell pre-ceding the outermost shell.
d. last electrons are filled up in the antepenultimate shell.
e. Includes some radioactive elements.
f. Some of them are used as catalyst in petroleum industry.
Answer:
b, d, e, f
Question 7.
The atomic number of four elements are given below. (The symbols ore not real)
A – 8
B – 10
C – 12
D – 18
a. Write the sub-shell electronic configuration of the elements,
b. Which of them are inert gases?
c. Write the chemical formula of the compound formed by two elements other than inert gases.
Answer:
a. A – 1s2 2s2 2p4
B – 1s2 2s2 2p6
C – 1s2 2s2 2p6 3s2
D – 1s2 2s2 2p6 3s2 3p6
b. B, D
c. CA, (C2 A2 is simplified and written as CA)
Question 8.
The subshell electronic configuration of two elements ends as follows. (Symbols are not real)
P – 3s2 Q – 3p4
a. Write the complete subshell electronic configuration.
b. Find out the oxidation state of each element.
c. The chemical formula of the compound formed by these elements is PQ. Is this statement correct? Justify your answer.
Answer:
a. P – 1s2 2s2 2p6 3s2
Q – 1s2 2s2 2p6 3s2 3p4
b. P = +2, Q = – 2 :
c. Right, valency of both P and Q is ‘2’
Question 9.
Match the following.
Answer:
Question 10.
The atomic number of two elements are given below.
Si – 14 Ni – 28
a. Write the subshell electronic configu-ration of these elements.
b. Find out the group and period of each element.
Answer:
a. Si – 1s2 2s2 2p6 3s2 3p2
Ni – 1s2 2s2 2p6 3s2 3p6 3d8 4s2
b. Si – Period Number – 3, Group number – 14 Ni – Period Number – 4, Group number – 10
Question 11.
The element ‘X’ has 4 shells and its 3d subshell has 6 electrons. (Symbol is not real)
a. Write the complete electronic configu-ration of the element.
b. What is its group number? Which is the block?
c. Write any two characteristics of the block to which element X belongs to.
d. From which subshell the electrons are lost when the element X shows +2 oxidation state.
Answer:
a. 1s2 2s2 2p6 3s2 3p6 3d6 4s2
b. Group number – 8, Block – d
c. All of them are metals
d – block elements are placed in group 3 to group 12
d. s – Sub shell
Question 12.
The outermost electronic configuration of the element A is 2s2 2p2. (Symbol is not real)
a. Find out the group number and block of the element.
b. Write the chemical formula of the compound formed by A when it combines with chlorine.
c. Write the complete electronic configuretion of the element just below ‘A’ in the j periodic table.
Answer:
a. Group number – 14, Block – P
b. ACl4
c. 1s2 2s2 2p6 3s2 3p2
Question 13.
The figure of an incomplete periodic table is given below.
a. Which one of these elements shows -2 oxidation state?
b. Which of these elements have 3 electrons in their outermost p subshell?
c. Which element has the highest atomic radius? Which one has the least?
d. Which of these elements show variable oxidation state?
e. Which of these elements has the highest ionization energy?
Answer:
a. G
b.F
c. The element having highest atomic radius – A
The element having lowest Atomic radius – H
d. D, C
e. H
Question 14.
Examine the given electronic configurations.
A – 1s2 2s2 2p6 3s2 3p6 3d10 4s2
B – 1s2 2s2 2p6 3s1
C – 1s2 2s2 2p1 3s2 3p6
D – 1s2 2s2 2p6 3s2
E – 1s2 2s2 2p6 3s2 3p6 4s2
a. Which of these elements belongs to 4th period?
b. Which elements belongs to the same group ?
c. Which element doesn’t participate in chemical reactions generally ?
d. Which element has highest metallic character ?
Answer:
a. A, E
b. B, E
c. C
d. E
Question 15.
The atomic number of the elements X and Y are 20, 26 respectively. When these elements combine with chlorine, three compounds XCl2, YCl2, YCl3 are formed.
a. What is the specialty of the oxidation number of Y, compared to that of X?
b. Explain the reason for this, on the basis of the subshell based electronic configuration.
Answer:
a. Element X has constant oxidation state. Y shows variable oxidation states.
b. X20 = 1s2, 2s2, 2p6, 3s2, 3p6, 4s2
X26 = 1s2, 2s2, 2p6, 3s2, 3p6, 4s2, 3d6
Y is a transitional element. In chemical reactions only two elections in ‘ s’ subshell or besides ‘s’ subshell electrons ‘d’ sub shell electrons also take part.
Periodic Table and Electronic Configuration Exam Oriented Questions and Answers
Very Short Answer Type Questions (Score 1)
Question 1.
Arrange the following sub-shells in the in-creasing order of energy 5p, 2s, 4f, 3s, 4s, 3d, 6s
Answer:
2s < 3s < 4s < 3d < 5p < 6s < 4f
Question 2.
Last electron in f-block elements goes to
a. Which shell? Outer shell/Penultimate shell /Antepenultimate shell
b. Which sub-shell? Outer f-subshell Penultimate f-subshell/Antepenulti mate f-subshell.
Answer:
a. Antepenultimate shell
b. Antepenultimate f-sub-shell
Question 3.
Sub-shell electronic configuration of X is given below.
1s2, 2s2, 2p5
a. The element Y is coming just below the element in same group. Then write the sub-shell electronic configuration of Y.
b. Write the sub-shell electronic configuration of the element next to X in same period.
Answer:
a. 1s2, 2s2, 2p6, 3s2, 3p2
b. Is2, 2s2, 2p6
Question 4.
A compound of vanadium pentoxide (V20;) is used as catalyst.
a. What is the oxidation state of vanadium in this compound?
b. How vanadium ion is represented?
c. Write the sub-shell electronic configuration of this ion (V – 23)
Answer:
a. +5
b. V5+
c. 1s2, 2s2, 2p6, 3s2, 3p6
Short Answer Type Questions (Score 2)
Question 5.
Find the wrong electronic configurations from the following. What is wrong in these?
a. 1s2,2s2,2p6,3s2,3p6,3d9,4s2
b. 1s2
c. 1s2, 2s1, 2p6
d. 1s2, 2s2, 2p6, 3s2, 3p2
Answer:
(a) and (c) are wrong electronic con figurations.
In (a) one electron from 4s is to be trans-ferred to 3d since completely filled configu-rations are more stable. So the correct electronic configuration is 1s2, 2s2, 2p6, 3s2, 3p6, 3d10, 4s1
In (c) electrons are filled in 2p only after filling electrons in 2s.
Question 6.
Group and period number of two elements are given.
P – group 17, period – 3
Q – group 2, period – 3
a. Write the sub-shell electronic configuration of each.
b Write the chemical formula of the compound formed by their combination.
Answer:
Answer:
a. P – 1s2, 2s2, 2p6, 3s2, 3p5
Q – 1s2, 2s2, 2p6, 3s2
b. Q is electropositive. P is electro negative;
∴Chemical formula QP2
Question 7.
Write the reason for the statement given
below.
a. d-block elements in the same period show similarity.
b. Transition elements show variable oxidation state.
Answer:
a. Valence shell electrons of d-block elements in same periods are almost same. Valence shell electrons are entering in chemical reaction. Therefore they shows similarity.
b. Energy of electrons in s-subshell and inner d- subshells are almost same. Therefore s- electrons or s and d electrons take part in chemical reaction and show variable oxidation state.
Short Answer Type Questions (Score 3)
Question 8.
Write the sub-shell electronic configuration of following elements. Predict the block, group and period. (Symbols are not real)
a. M – 27 b. N – 19 c. P – 15
Answer:
a. 1s2, 2s2, 2p6, 3s2, 3p6, 3d7, 4s2
block – d; group – 9; period – 4.
b. 1s2, 2s2, 2p6, 3s2, 3p6, 4s1
block – s; group – 1; period – 4
c. 1s2, 2s2, 2p6, 3s2, 3p3
block – p; group – 15; period – 3
Question 9.
Observe the model of periodic table.
a. Which element is having S electrons in valence shell?
b. Which elements are having 2 electrons in valence sub-shell?
c. Which element is having last electron in3p?
d. Which element ends with electronic configuration 4d5, 5s1 ?
Answer:
a. B;
b.A, C;
c. C, D;
d. E
Question 10.
Calculate oxidation state of transition elements in the following compounds.
Answer:
a. KMnO4 – Mn – 7+
b. Cr2 O3 – Cr – 3+
c. K2Cr2O7 – Cr – 6+
Question 11.
Atomic number of some elements are given. A – 15, B – 8, C – 11, D – 18, E – 20, F – 34, G – 10
a. Which are the elements in same period?
b. Which are the elements in same group?
Answer:
A -1s2, 2s2, 2p6, 3s2, 3p3
(group -15 period – 3)
B – 1s2, 2s2, 2p4 (group –16 period – 2)
C – 1s2, 2s2, 2p6, 31 (group – 1 period – 3)
D – 1s2, 2s2, 2p6, 3s2, 3p6 (group – 18 period – 3)
E – 1s2, 2s2, 2p6, 3s2, 3p6, 4s2.(group – 2 period – 4)
F – 1s2, 2s2, 2p6, 3s2, 3p6, 3d10, 4s2, 4p4 (group – 16 period – 4)
G – 1s2, 2s2, 2p6 (group – 18 period – 2)
a. A, D same period ;
B, G same period 1
b. B, F same group ;
D, G same group
Long Answer Type Questions (Score 4)
Question 12.
Electronic configuration of some elements are given. Write answers to the following questions.
i. [Ne] 3s2
ii. [Ar ] 3d2,4s2
iii. [Xe] 6s2
iv. [Ne]3s2
v [Ne] 3s2,3p5
a. Which metal is having high reactivity?
b. Which is having possibility of formation of colored compounds?
c. Which is the non-metal?
d Which element shows the possibility of +2 oxidation state?
Answer:
a. [Xe] 6s1
b. [Ar ] 3d2, 4s2
c. [Ne] 3s2, 3p5
d. [Ne] 3s2,[Ar] 3d2, 4s2
Question 13.
Pick the wrong statement from the following.
a. Elements with atomic number 5 belong to group 15.
b. Electronic configuration of scandium (Atomic number 21) is 2,8,8,3.
c. d-block elements are known as transition elements.
d. All s-block elements are metals.
Answer:
a. Wrong. It belongs to group 13.
b. Wrong. Electronic configuration
2,8,9,2 (1s2, 2s2, 2p6, 3s2, 3p6,3d1, 4s2)
c. Correct .
d. Correct
Question 14.
Look at the Bohr model of X-atom.
a. Write the sub-shell electronic configuration of this atom.
b. Mention the compounds in which d-subshell electrons are taking part in chemical reaction during their formation.
XCl2, XO2, X2O7
c. Write the electronic configuration of X ions in the above three compounds.
Answer:
a. 1s2, 2s2, 2p6, 3s2, 3p6, 3d5, 4s2
b. XCl2 – ion X2+ (electrons in 4s only)
XO2 – ion X+4 (2 electrons in 4s and 2 electrons in 3d)
X2O7 – ion X7+ (2 electrons in 4s and 5 electrons in 3d)
XO2, X2O7 d – subshell electrons are taking part in chemical reaction during the formation of X207
c. X2+ – 1s2, 2s2, 2p6, 3s2, 3p6, 3d5
X4+ – 1s2, 2s2, 2p6, 3s2, 3p6, 3d3
X7+ – 1s2, 2s2, 2p6, 3s2, 3p6
Question 15.
Select the suitable one from the following columns A, B, C.
Answer: