KT 8 Maths

KSEEB Solutions for Class 8 Maths Chapter 3 Axioms, Postulates and Theorems Ex 3.3

KSEEB Solutions for Class 8 Maths Chapter 3 Axioms, Postulates and Theorems Ex 3.3

Karnataka Board Class 8 Maths Chapter 3 Axioms, Postulates and Theorems Ex 3.3

Question 1.
Find all the angles in the following

KSEEB Solutions for Class 8 Maths Chapter 3 Axioms, Postulates and Theorems Ex. 3.3 1
Answer:
∠CMP + ∠PMD = 180° [Linear pair]
∠CMP+ 135° = 180°
∠CMP = 180° – 135
∠CMP = 45°
∠LMD = ∠CMP = 45° [Vertical opposite angles]
∠LMC =∠PMD = 135° [Vertical opposite angles]
∠ALM = ∠ LMC = 135° [Alternate angles]
∠BLM = ∠ LMC = 135° [Alternate angle]
∠QLB = ∠LMD = 45° [Corresponding angles]
∠QLA = ∠ LMC = 135° [Corresponding angles

Question 2.
Find the value of x in the diagram below.
KSEEB Solutions for Class 8 Maths Chapter 3 Axioms, Postulates and Theorems Ex. 3.3 2
Answer:
∠PQS = ∠EPT = 130° [Corresponding angle]
∠PQS + ∠SQR = 180° [Linear pair]
SQR = 180 – 130
∠SQR = 50°
∠QRS + ∠FRS = 180° [Linear pair]
∠QRS + 90° =180°
∠QRS = 180 – 90
∠QRS = 90°
∠SQR+ ∠QRS +∠QSR = 180°
[Sum of the angles of triangle is 180° ]
50 + 90 + ∠QSR = 180°
140 + ∠QSR = 180°
∠QSR = 180 – 140
∠QSR =40°
∠TSD = ∠QSR [Vertically opposite angles]
x = 40°.

Question 3.
Show that if a straight line is perpendicular to one of the two or more parallel lines, then it is also perpendicular to the remaining lines.
Answer:
KSEEB Solutions for Class 8 Maths Chapter 3 Axioms, Postulates and Theorems Ex. 3.3 3

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