KSEEB Solutions for Class 8 Maths Chapter 8 Linear Equations in One Variable Ex 8.1
KSEEB Solutions for Class 8 Maths Chapter 8 Linear Equations in One Variable Ex 8.1
Karnataka Board Class 8 Maths Chapter 8 Linear Equations in One Variable Ex 8.1
1. Solve the following:
Question i.
x + 3 = 11
Answer:
x + 3 = 11
x = 11 – 3
x = 8
Question ii.
y – 9 = 21
Answer:
y – 9 = 21
y = 21 + 9
y = 30
Question iii.
10 = z + 3
10 = z + 3 10-3 =z
7 = z or z = 7
2. Solve the equations :
Question i.
5x = 3x + 24
Answer:
5x = 3x + 24
2x = 24
x = 24/2
x = 12
Question ii.
8t + 5 = 2t – 31
Answer:
8t + 5 = 2t – 31
6t = -36
t = −36/6
t = -6
Question iii.
7x -10 = 4x + 11
Answer:
7x – 10 = 4x + 11
7x – 4x = 11 + 10
3x = 21
x = 21/3
x = 7
Question iv.
4z + 3 = 6 + 2z
Answer:
4z + 3 = 6 + 2z
4z – 2z = 6 – 3
2z = 3
Question v.
2x – 1 = 14 – x
Answer:
2x – 1 = 14 – x
2x + x = 14 + 1
3x = 15
x = 15/3
x = 5
Question vi.
6x + 1 = 3(x -1) + 7
Answer:
6x + 1 = 3(x —1) + 7
6x + l =3x-3 + 7
6x + l = 3x + 4
6x – 3x = 4 – 1
3x = 3
x = 3/3
x = 1
Question ix.
3(x + 1) = 12 + 4(x – 1)
Answer:
3(x + 1)= 12 + 4(x – 1)
3x + 3 = 12 + 4x – 4
3x + 3 = 4x + 8
3x – 4x = 8 – 3
-x = 5
x = -5
Question x.
2x – 5 = 3(x – 5)
Answer:
2x – 5 = 3(x – 5)
2x – 5 = 3x – 15
2x – 3x = -15 + 5
-x = -10
x= 10
Question xi.
6(1 – 4x) + 7(2 + 5x) = 53
Answer:
6( 1 – 4x) + 7(2 + 5x) = 53
6 – 24x+ 14 + 35x = 53
35x – 24x + 6 + 14 = 53
11x+ 20 = 53
11x = 53 – 20
x = 33/11
x = 3
Question xii.
3(x + 6) + 2(x + 3) = 64
Answer:
3(x + 6) + 2(x + 3) = 64
3x + 18 + 2x + 6 = 64
3x + 2x + 18 + 6 = 64
5x + 24 = 64
5x = 64 – 24
5x = 40
x = 40/5
∴ x = 8
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