Maharashtra Board 9th Class Maths Part 1 Practice Set 4.4 Solutions Chapter 4 Ratio and Proportion
Maharashtra Board 9th Class Maths Part 1 Practice Set 4.4 Solutions Chapter 4 Ratio and Proportion
Practice Set 4.4 Algebra 9th Std Maths Part 1 Answers Chapter 4 Ratio and Proportion
Question 1.
Fill in the blanks of the following.
Solution:
Question 2.
5m – n = 3m + 4n, then find the values of the following expressions.
Solution:
5m – n = 3m + 4n … [Given]
∴ 5m – 3m = 4n + n
∴ 2m = 5n
Question 3.
Solve:
i. If a(y + z) = b(z + x) = c(x + y) and out of a, b, c no two of them are equal, then show that, y−z/a(b−c)=z−x/b(c−a)=x−y/c(a−b).
Solution:
Here, no two of a, b and c are equal.
∴ values of (b – c), (c – a) and (a – b) are not zero.
a(y + z) = b(z + x) = c(x + y) … [Given]
ii. If x/3x−y−z=y/3y−z−x=z/3z−x−y and x + y + z ≠ 0, then show that the value of each ratio is equal to 1.
Solution:
iii. x/3x−y−z=y/3y−z−x=z/3z−x−y and x + y + z ≠ 0,then show that a+b/2.
Solution:
iv. If y+z/a=z+x/b=x+y/c , then show that x/b+c−a=y/c+a−b=z/a+b−c.
Solution:
v. If 3x−5y/5z+3y=x+5z/y−5x=y−z/x−z , then show that every ratio = x/y.
Solution:
Ratio And Proportion Class 9 Practice Set 4.4 Question 4.
Solve:
Solution:
∴ 7(4x – 5)3(2x + 3)
∴ 28x – 35 = 6x + 9
∴ 28x – 6x = 9 + 35
∴ 22x = 44
∴ x = 2
∴ x = 2 is the solution of the given equation.
ii. 5y2+40y−12/5y+10y2−4=y+8/1+2y
∴ y + 8 = 3(1 + 2y)
∴ y + 8 = 3 + 6y
∴ 8 – 3 = 6y – y
∴ 5 = 5y
∴ y = 1
∴ y = 1 is the solution of the given equation.
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