NCERT Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.5

NCERT Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.5

These NCERT Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.5 Questions and Answers are prepared by our highly skilled subject experts.

NCERT Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Exercise 2.5

Question 1.
Which is greater?
(i) 0.5 or 0.05
(ii) 0.7 or 0.5
(iii) 7 or 0.7
(iv) 1.37 or 1.49
(v) 2.03 or 2.30
(vi) 0.8 or 0.88
Answer:
(i) Comparing the digits at tenths place, we have
5 > 0
∴ 0.5 >0.05
So, 0.5 is greater.

(ii) Comparing the digits at tenths places, we have
7 > 5
∴ 0.7 > 0.5
So, 0.7 is greater.

(iii) Comparing the digits at ones place, we have
7 > 0
∴ 7 > 0.7
So, 7 is greater.

(iv) Since the digits at ones place are same, comparing the digits at tenths place, we have
3 < 4
∴ 1.37 <1.49
So, 1.49 is greater.

(v) Since the digits at ones place are same, comparing the digits at tenths place, we have
0 < 3
∴ 2. 03 < 2.30
So, 2.30 is greater.

(vi) 0.8 can be written as 0.80. Now, digits at tenths place are same, comparing the digits at hundredths place, we have
0 < 8
∴ 0.80 <0.88
So, 0.88 is greater.

Question 2.
Express as rupees using decimals:
(i) 7 paise
(ii) 7 rupees 7 paise
(iii) 77 rupees 77 paise
(iv) 50 paise
(v) 235 paise.
Answer:

Question 3.
(i) Express 5 cm in metre and kilometre
(ii) Express 35 mm in cm, m, and km
Answer:

Question 4.
Express in kg:
(i) 200 g
(ii) 3470 g
(iii) 4 kg 8 g
Answer:

Question 5.
Write the following decimal numbers in the expanded form:
(i) 20.03
(ii) 2.03
(iii) 200.03
(iv) 2.034
Answer:

Question 6.
Write the place value of 2 in the following decimal numbers:
(i) 2.56
(ii) 21.37
(iii) 10.25
(iv) 9.42
(v) 63.352.
Answer:
(i) In 2.56, the digit 2 is at the ones place
∴ place value of 2 is 2 × 1 = 2.

(ii) In 21.37, the digit 2 is at the tens place
∴ place value of 2 is 2 × 10 = 20.

Question 7.
Dinesh went from place A to place B and from there to place C. A is 7.5 km from B and B is 12.7 km from C. Ayub went from place A to place D and from there to place C. D is 9.3 km from A and C is 11.8 km from D. Who travelled more and by how much?
Answer:
Distance from A to B = 7.5 km
Distance from B to C = 12.7 km
Distance from A to C through
B = (7.5 + 12.7) km
= 20.2 km
∴ Distance travelled by Dinesh = 20.2 km

Again
Distance from A to D = 9.3 km
Distance from D to C = 11.8 km
Distance from A to C through D
= (9.3 + 11.8) km
= 21.1 km
∴ Distance travelled by Ayub = 21.1 km 21. 1 > 20.2
∴ Ayub travelled more distance.
Difference = 21.1 km – 20.2 km
= 0.90 km (or) 900 m
∴ Ayub travelled more distance by 900 m

Question 8.
Shyama bought 5 kg 300 g apples and 3 kg 250 g mangoes. Sarala bought 4 kg 800 g oranges and 4 kg 150 g bananas. Who bought more fruits?
Answer:
Since, Shyama bought 5 kg 300 g apples and 3 kg 250 g mangoes
Total fruits bought by Shyama = 5 kg
300 g + 3 kg 250 g = 8 kg 550 g
Since, Sarala bought 4 kg 800 g oranges and 4 kg 150 g bananas
Total fruits bought by Sarala
= 4 kg 800 g + 4 kg 150 g = 8 kg 950 g
8.950 > 8.550
So, Sarala bought more fruits
Difference in weight = 8 kg 950 g – 8 kg 550 g = 0 kg 400 g
= 400 g or 400/1000kg = 0.4 kg

Question 9.
How much less is 28 km than 42.6 km?
Answer:
Difference = 42.6 km – 28 km = 14.6 km 28 km is less than 42.6 km by 14.6 km