NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Ex 10.5
NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Ex 10.5
These NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Ex 10.5 Questions and Answers are prepared by our highly skilled subject experts.
NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Exercise 10.5
Question 1.
Construct the right-angled ∆PQR, where m∠Q = 90° QR = 8 cm and PR = 10 cm. Ans: Steps of Construction
(i) Draw a rough diagram with measures marked on it.
(ii) Draw a line segment QR = 8 cm.
(iii) At Q, Construct ∠RQX = 90° .
(iv) With centre at R and radius 10 cm, draw an arc to cut QX at P.
(v) Join PR.
Thus, PQR is the required right-angled triangle.
Question 2.
Construct a right-angled triangle whose hypotenuse is 6 cm long and one of the legs is 4 cm long.
Answer:
Steps of Construction
(i) Draw a rough diagram with measures marked on it.
(ii) Draw a line segment QR = 4 cm.
(iii) At Q, construct ∠RQX = 90
(iv) With R as centre and radius 6 cm draw an arc to cut QX at R
(v) Join PR.
Thus, PQR is the required right angled triangle.
Question 3.
Construct an isosceles right-angled triangle ABC, where m∠ACB = 90° and AC = 6 cm.
Answer:
Steps of Construction
(i) Draw a rough diagram with measures marked on it.
(ii) Draw a line segment AC = 6 cm.
(iii) At ‘C’, construct ∠ACX – 90°.
(iv) With centre ‘C’ and radius 6 cm, draw an arc to cut CX at B.
(v) Join AB.
Thus, ∆ABC is the required isosceles right-angled triangle.
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