Samacheer Kalvi 10th Maths Solutions Chapter 3 Algebra Ex 3.10

Samacheer Kalvi 10th Maths Solutions Chapter 3 Algebra Ex 3.10

Tamilnadu Samacheer Kalvi 10th Maths Solutions Chapter 3 Algebra Ex 3.10

10th Maths Exercise 3.10 Samacheer Kalvi Question 1.
Solve the following quadratic equations by factorization method
(i) 4x² – 7x – 2 = 0
(ii) 3(p² – 6) = p(p + 5)
(iii) √a(a−7)=3√2
(iv) √2x2+7x+5√2=0
(v) 2x² – x + 1/8 = 0
Solution:

(ii) 3(p² – 6) = p(p + 5)
3p² – 18 = p² + 5p ⇒ 39² – 5p – 18 = 0
⇒ 2p² – 5p – 18 = 0
⇒ (2p – 9) (p + 2) = 0 ⇒ p = 9/2, -2

(iii) √a(a−7)=3√2
Squaring on both sides
a(a – 7) = 9 × 2
a² – 7a – 18 = 0
a² – 9a + 2a – 18 = 0
a(a – 9) + 2(a – 9) = 0
(a – 9) (a + 2) = 0
⇒ a = 9, a = -2

(v) 2x² – x + 1/8 = 0
16x² – 8x + 1 = 0
16x² – 4x – 4x + 1 = 0
4x(4x – 1) – 1(4x – 1) = 0
(4x – 1) (4x – 1) = 0
⇒ x = 1/4,1/4

10th Maths Exercise 3.10 Question 2.
The number of volleyball games that must be scheduled in a league with n teams is given by G(n) = n2−n/2 where each team plays with every other team exactly once. A league schedules 15 games. How many teams are in the league?
Answer:
Number of games = 15
G(n) = n2−n/2
n2−n/2 = 15
n² – n = 30 ⇒ n² – n – 30 = 0
⇒ n²– 6n – 5n – 30 = 0
(n – 6) (n + 5) = 0
n – 6 = 0 or n + 5 = 0
[Note: – 5 is neglected because number of team is not negative]
n = 6 or n = -5
∴ Number of teams = 6