Samacheer Kalvi 10th Maths Solutions Chapter 3 Algebra Ex 3.17

Samacheer Kalvi 10th Maths Solutions Chapter 3 Algebra Ex 3.17

Tamilnadu Samacheer Kalvi 10th Maths Solutions Chapter 3 Algebra Ex 3.17

10th Maths Exercise 3.17 Answers Question 1.

(i) A + B = B + A
(ii) A + (-A) = (-A) + A = 0
Solution:

10th Maths Exercise 3.17 Question 2.

Solution:

Ex 3.17 Class 10 Question 3.

Solution:

10th New Syllabus Maths Exercise 3.17 Question 4.

(i) B – 5A
(ii) 3A – 9B
Solution:

Exercise 3.17 Class 10 Question 5.
Find the values of x, y, z if

Solution:

x – 3 = 1 ⇒ x = 4
3x – z = 0
3(4) – z = 0
-z = -12 ⇒ z = 12
x + y + 7 = 1
x + y = -6
4 + y = -6
y = -10
x = 4, y = -10, z = 12

(ii) [x  y−z  z+3]+[y  4  3]=[4  8  16]
x + y = 4 ……………. (1)
y – z + 4 = 8 ………….. (2)
z + 3 + 3 = 16 ………….. (3)
From (3), we get z = 10
From (2), we get y – 10 + 4 = 8
From (2), we get y = 14
From (1) we get x + 14 = 4
x = -10
x = -10, y = 14, z = 10

10th Maths Exercise 3.17 Answers 2021 Question 6.

Solution:

10th Maths Exercise 3.17 Samacheer Kalvi Question 7.
Find the non-zero values of x satisfying the matrix equation

Solution:

Exercise 3.17 Question 8.

Solution:
x² – 4x = 5
y² – 2y = 8
y² – 2y – 8 = 0
(y – 4)(y + 2) = 0
y = 4, -2
x² – 4x – 5 = 0
(x – 5)(x + 1) = 0
x = 5, -1
x = -1, 5, y = 4, -2