Samacheer Kalvi 6th Maths Solutions Term 1 Chapter 1 Numbers Intext Questions
Samacheer Kalvi 6th Maths Solutions Term 1 Chapter 1 Numbers Intext Questions
Tamilnadu Samacheer Kalvi 6th Maths Solutions Term 1 Chapter 1 Numbers Intext Questions
Try These (Textbook Page No. 2)
Question 1.
The Successor of 4576 is ____
Solution:
4577
Question 2.
The Predecessor of 8970 is ____
Solution:
8969
Question 3.
999 + 1 equals _____
Solution:
1000
Question 4.
10000 – 1 equals _____
Solution:
9999
Question 5.
The Predecessor of the smallest 5 digit number is ____
Solution:
Greatest 4 digit number 9999
Try These (Textbook Page No. 4)
Question 1.
Give 3 examples where the number of things counted by you would be a 5 digit number or more.
Solution:
- Number of stars in the sky.
- The number of people living in Tamilnadu.
- The number of accidents in India in the year 2017.
Question 2.
There are ten lakh people in a district. What would be the population of 10 such districts?
Solution:
Number of people in the district = 10,00,000
.’. Population of 10 such districts = 10,00,000 × 10 = 1,00,00,000
Total population of 10 districts would be one crore.
10 lakh = 10,000 Hundreds
Question 3.
The Government spends rupees 2 crores for education in a particular district every month. What would be its expenditure for over 10 months?
Solution:
Expenditure for one month = 2 crores,
Expenditure for ten months = 2,00,00,000 × 10 = 20,00,00,000
Expenditure for 10 months = twenty crores.
Try These (Textbook Page No. 5)
Question 1.
Complete the table:
Solution:
Try These (Textbook Page No. 6)
Question 1.
Read and expand the following numbers:
(i) 2304567
(ii) 4509888
(iii) 9553556
Solution:
(i) Number: 23,04,567
Expanded form: 2 × 1000000 + 3 × 100000 + 0 × 10000 + 4 × 1000 + 5 × 100 + 6 × 10 + 7 × 1
Read as: Twenty Three Lakh Four Thousand Five Hundred and Sixty Seven
(ii) Number: 45,09,888
Expanded form: 4 × 1000000 + 5 × 100000 + 0 × 10000 + 9 × 1000 + 8 × 100 + 8 × 10 + 8 × 1
Read as: Forty Five Lakh Nine Thousand Eight Hundred and Eighty Eight
(iii) Number: 95,53,556
Expanded form: 9 × 1000000 + 5 × 100000 + 5 × 10000 + 3 × 1000 + 5 × 100 + 5 × 10 + 6 × 1
Read as: Ninety Five Lakh Fifty Three Thousand Five Hundred and Fifty Six
Question 2.
How many hundreds are there in 10 lakh?
Solution:
There are four places to the left of a Hundred.
Question 3.
10 lakh candidates write the Public Exam this year. If each exam centre is allotted with 1000 candidates. How many exam centres would be needed?
Solution:
Candidate for one centre = 1000
For 10 lakh people
10,00,000
Ten lakh contains = 10,00,000/1000 = 1000 Thousands
For 10 lakh people 1000 centres are needed
Try These (Textbook Page No. 7)
Question 1.
Find the place value of underlined digits
(i) 3841567
(ii) 94,43,810
Solution:
(i) Place value of 8 is 8 × 1,00,000 = 8,00,000 (Eight Lakh)
(ii) Place value of 4 is 4 × 10,000 = 40,000 (Forty Thousand)
Question 2.
Write down the numerals and place value of 5 in the numbers represented by the following number names.
(i) Forty-Seven Lakh Thirty Fight Thousand Five Hundred Sixty One.
(ii) Nine Crore Eighty-Two lakh Fifty Thousand Two Hundred Forty-One
(iii) Nineteen Crore Fifty-Seven Lakh Sixty Thousand Three Hundred Seventy
Solution:
(i) 47,38,561
Place value of 5 is 5 × 100 = 500 (Five Hundred)
(iii) 9,82,50,241
Place value of 5 is 5 × 10000 = 50,000 (Fifty Thousand)
(iv) 19,57,60,370
Place value of 5 is 5 × 10,00,000 = 50,00,000 (Fifty Lakhs)
Try These (Textbook Page No. 9)
Question 1.
Identify the incorrect places of comma and rewrite correctly. Indian System: 56, 12, 34, 0, 1, 5 ; 9,90,03,2245
International System: 7,5613,4534; 30,30,304,040
Indian System: 56, 12, 34, 015; 99,00,32,245
Solution:
Indian System: 56,12,34,015; 99,00,32,245
International System: 756,134,534 ; 3,030,304,040
Try These (Textbook Page No. 13)
Question 1.
Write the numbers in ascending order: 688, 9, 23005, 50, 7500.
Solution:
Ascending order: 9, 50, 688,7500, 23005
9 < 50 < 688 < 7500 < 23005
Question 2.
Find the least and greatest among the numbers: 478, 98, 6348,3, 6007, 50935
Solution:
The lease number is 3.
The greatest number is 50935
Try These (Textbook Page No. 14)
Question 1.
Compare the two numbers and put <, > and = using a place value chart.
Solution:
(i) 15475, 3214
Comparing the place value using a place value chart.
comparing the place values from left we have 15475 > 3214
(ii) 73204, 973561
Place value chart
comparing the digits or two numbers 73204 < 973561
(iii) 8975430, 8975430
From the place value chart comparing tne digits trom left 8 = 8, 9 = 9, 7 = 7, 5 = 5, 4 = 4, 3 = 3, 0 = 0
8975430 = 8975430
(iv) 1899799, 1899799.
From the place value chart comparing the digits of the two numbers from the highest place value we have 1 = 1, 8 = 8, 9 = 9, 9 = 9, 7 = 7, 9 = 9, 9 = 9
1899799 = 1899799
Try These (Textbook Page No. 16)
Question 1.
The area in sq.km of 4 Indian states are given below:
List the areas of the above 4 Indian States in the ascending and the descending order.
Solution:
We can prepare place value chart
5 digit number 38,863 is the least value.
Comparing digits of other 6 digit numbers from left.
1 = 1 = 1, 3 < 6 < 9
Ascending order = 38,863 < 1,30,058 < 1,62,968 < 1,91,791
Kerala < Tamilnadu < Andhra Pradesh < Karnataka
Descending order = 1,91,791 > 1,62,968 > 1,30,058 > 38,863
Karnataka > Andhra Pradesh > Tamilnadu > Kerala
Try These (Textbook Page No. 17)
Question 1.
In the same way, try placing the digit 4 in thousandth place and get six different 4-digit numbers. Also, make different 4-digit numbers by fixing 8 and 5 in the thousandth place.
Solution:
Question 2.
In the same way, make different 4 digit numbers by exchanging the digits and check every time whether the number made is small or big.
1432 < 4321 4321 > 3214
3214 > 2143
Solution:
Question 3.
Pedometer used in walking practice contains 5 digit number. What could be the largest measure?
Solution:
99,999
Try These (Textbook Page No. 25)
Question 1.
Round off the following numbers to the nearest ten
(i) 57
(ii) 189
(iii) 3,956
(iv) 57,312
Solution:
(i) 57
Given number = 57
Place value to be rounded off is ten.
Digit in tens place is 5.
Digit to’the right is 7 > 5
Adding 1 to 5 = 1 + 5 = 6
Changing the digits to the right of 6 to zero = 60
rounded off number is 60.
(ii) 189
Place value to be rounded off is ten
Digit is ten places is 8
Digit to the right is 9 > 5
Adding 1 to 8 = 1 + 8 = 9.
changing the digits to the right of 19 to zero = 190
Required rounded off number is 190
(iii) 3956
Place value to be rounded off is ten.
Digit in tens place is 5
Digit to the right is 6 > 5
Adding 1 to 5 = 1 + 5 = 6
Changing the right digits of 396 to zero = 3960
Required rounded off number is 3960.
(iv) 57312
Place value to be rounded off is ten.
Digit in tens place is 1
Digit to the right is 2 < 5
Leaving the number 2 as it is changing the digits to the right of 5731 to zero = 57310.
The rounded number is 57310
Question 2.
Round off the following numbers to the nearest ten, hundred and thousand.
(i) 9,34,678
(ii) 73,43,489
(iii) 17,98,45,673
Solution:
(i) 9,34,678
Nearest Tens: 9,34,680
Nearest Hundreds: 9,34,700
Nearest Thousands: 9,35,000
(ii) 73,43,489
Nearest Tens: 73,43,490
Nearest Hundreds: 73,43,500
Nearest Thousands: 73,43,000
(iii) 17,98,45,673
Nearest Tens: 17,98,45,670
Nearest Hundreds: 17,98,45,700
Nearest Thousands: 17,98,46,000
Question 3.
The tallest mountain in the world Mount Everest, located in Nepal is 8,848 m high. Its height can be rounded off to the nearest thousands as ______
Solution:
9000 m
Try These (Textbook Page No. 27)
Question 1.
Estimate the sum and difference:
8457 and 4573
Solution:
(a) Sum
8457 ⇒ 8000
4573 ⇒ 5000
Sum = 13,000
(b) Difference
8457 ⇒ 8000
4573 ⇒ 5000
Difference = 3,000
Question 2.
Estimate the product 39 × 53
Solution:
39 ⇒ 40
53 ⇒ 50
Product 40 × 50 = 2000
Question 3.
Estimate the quotient 5546 ÷ 524
Solution:
5546 ⇒ 5500
524 ⇒ 500
Quotient is 11
Try These (Textbook Page No. 29)
Question 1.
Find the value of 6 + 3 + 8 and 3 + 6 + 8
(i) Are the same?
(ii) Is there any other way of arranging these three numbers?
Solution:
6 + 3 + 8 = 3 + 6 + 8 = 17
(i) Yes, 6 + 3 + 8 = 3 + 6 + 8 = 17, Both are same
(ii) Yes, we can arrange these numbers as
3 + 8 + 6 = 8 + 6 + 3 = 8 + 3 + 6 = 6 + 8 + 3
Question 2.
Find the value of 5 × 2 × 6 and 2 × 5 × 6
(i) Are the same?
(ii) Is there any other way of arranging these three numbers?
Solution:
5 × 2 × 6 = 2 × 5 × 6 = 60
(i) Yes, they are the same
(ii) They can be arranged as
2 × 6 × 5 = 6 × 5 × 2 = 5 × 6 × 2 = 6 × 2 × 5.
Question 3.
Is 7 – 5 the same as 5 – 7? Why?
Solution:
7 – 5 ≠ 5 – 7.
Because subtraction is not commutative [∵ 7 – 5 = 2; 5 – 7 = -2]
Question 4.
What is the value of (15 – 8) – 6? Is it the same as 15 – (8 – 6)? Why?
Solution:
(15 – 8) – 6 = 7 – 6 = 1
(15 – 8) – 6 = 1
It is not same as 15 – (8 – 6).
15 – (8 – 6) = 15 – 2 = 13
(15 – 8) – 6 ≠ 15 – (8 – 6)
Question 5.
What is 15 ÷ 5? Is it the same as 5 ÷ 15? Why?
Solution:
(i) 15 ÷ 5 = 3
(ii) 15 ÷ 5 ≠ 5 ÷ 15
(iii) Division is not commutative for whole numbers.
Question 6.
What is the value of (100 ÷ 10) ÷ 5? Is it the same as 100 ÷ (10 ÷ 5)? Why?
Solution:
(i) (100 ÷ 10) ÷ 5 = 10 ÷ 5 = 2
(ii) 100 ÷ (10 ÷ 5) ≠ (100 ÷ 10) ÷ 5
(iii) Because division of whole numbers are not associative.
Also 100 ÷ (10 ÷ 5) = 100 ÷ 2 = 50
But (100 ÷ 10) ÷ 5 = 10 ÷ 5 = 2 = 50 ≠ 2
(i. e) (100 ÷ 10) ÷ 5 ≠ 100 ÷ (10 ÷ 5)
Try These (Textbook Page No. 30, 32, 33)
Question 1.
Use at least three different pairs of whole numbers to verify that subtraction is not commutative
Solution:
(a) 7 and 20
20 – 7 ≠ 7 – 20
(b) 300 and 100
300 – 100 ≠ 100 – 300
(c) 60 and 5
60 – 5 ≠ 5 – 60
Question 2.
Is 10 ÷ 5 the same as 5 ÷ 10? Justify it by taking two more combinations of numbers
Solution:
10 ÷ 5 ≠ 5 ÷ 10
Example:
(a) 20 ÷ 10 ≠ 10 ÷ 20 i.e. 2 ≠ 1/2
(b) 100 ÷ 50 ≠ 50 ÷ 100 i.e. 2 ≠ 1/2
Solution:
Question 5.
How will you read the large number given below?
731, 687, 303, 715, 884, 105, 727
Solution:
This is read as 731 quintillions, 687 quadrillions, 303 trillion, 715 billion, 884 million, 105 thousand, 727.