Samacheer Kalvi 6th Maths Solutions Term 1 Chapter 4 Geometry Additional Questions
Samacheer Kalvi 6th Maths Solutions Term 1 Chapter 4 Geometry Additional Questions
Tamilnadu Samacheer Kalvi 6th Maths Solutions Term 1 Chapter 4 Geometry Additional Questions
Question 1.
From the given figure, name the parallel lines
(a) An infinite number of lines can pass through one given point.
(b) Exactly one and only one line can pass through two given points.
Question 4.
A line contains how many points?
(a) minimum?
(b) maximum?
Solution:
(a) A line contains a minimum of two points.
(b) A line contain a maximum of infinitely many points.
Question 5.
Write the (a) maximum and (b) the minimum number of point of intersection of three lines.
Solution:
Maximum – 3 points of intersection
Minimum – No point of intersection
Fill in the blanks.
Question 6.
Complementary angle of 20° is _____
Solution:
70°
Question 7.
The supplementary angle of 90° is _____
Solution:
90°
Question 8.
78°, 12°, ______
Solution:
Complementary angle
Answer the following question.
Question 9.
∠ABD =?
Solution:
On Sum of complementary angles = 90°
∠ABC = 90°
∠CBD = 30°
∠ABD = ∠ABC – ∠DBC = 90° – 30° = 60°
∠ABD = 60°
Complementary angle of 30° = 60°
Question 10.
In the following figure, name the angles.
Solution:
∠AOB, ∠BOZ, ∠AOZ
Question 11.
Write the alternate name of the angle ∠XYZ in the given figure.
Solution:
∠Y or ∠ZYX
Question 12.
Draw the diagram of two angles having only one common point.
Solution:
∠COD and ∠AOB have the point ‘O’ in common
Question 13.
What are the supplementary and complementary angles of 60°?
Solution:
Supplementary angle is 120°
Complementary angle is 30°
Question 14.
How many lines can you draw passing through three collinear points? Draw the figure also.
Solution:
Only one.
Question 15.
Write the maximum number of lines that can pass through a single point.
Solution:
Infinite.
Question 16.
Use a protractor to draw an angle 45°.
Solution:
Construction:
1. Drawn the base ray PQ.
2. Placed the centre of the protractor at the vertex P. Lined up the ray PQ−→− with the 0° line. Then drawn and labelled a pointed (R) at the 45° mark on the inner scale (a) anticlockwise and (b) outer scale (clockwise)
3. Removed the protractor and drawn at PR−→ to complete the angle
Now ∠P = ∠QPR = ∠RPQ = 45°.
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