Samacheer Kalvi 7th Maths Solutions Term 1 Chapter 6 Information Processing Ex 6.2

Tamilnadu Samacheer Kalvi 7th Maths Solutions Term 1 Chapter 6 Information Processing Ex 6.2

Miscellaneous Practice Problems

Question 1.
Make a model of a fish using the given tetromino shapes

Complete the given rectangle using the given tetromino shapes.
Solution:

Question 2.
Complete the given rectangle using the given tetromino shapes.

Solution:

Question 3.
Shade the figure completely, by using five Tetromino shapes only once.

Solution:

Question 4.
Using the given tetrominoes with numbers on it complete the 4 × 4 magic square?

Solution:

Question 5.
Find the shortest route to Vivekanandar Memorial Hall from the Mandapam using the given map.

Solution:
Possible routes from Mandapam to Vivekandar Memorial are

route 1:
(a) Mandapam ➝ Pullivasal Island ➝ Krusadai Island ➝ Vivekanandar Memorial Hall.
Distance = 6 Km + 2 Km + 1.5 Km = 9.5 Km

route 2:
(b) Mandapam ➝ Krusadai Island ➝ Vivekanandar Memorial Hall.
Distance = 7 Km + 1.5 Km = 8.5 Km
8.5 km < 9.5 km
∴ Shortest route : Mandapam ➝ Krusadai Island ➝ Vivekanandar Memorial Hall.

Challenge Problems

Question 6.
Fill in 4 × 10 rectangle completely, using all the five tetrominoes twice.
Solution:

(more possible ways are there)

Question 7.
Fill in 8 × 5 rectangle completely, using all the five tetrominoes twice.
Solution:

(more possible way are there)

Question 8.
Observe the picture and answer the following.
(i) Find all the possible routes from A to D.
(ii) Find the shortest distance between E and C.
(iii) Find all the possible routes between B and F with distance. Mention the shortest route.

Solution:
(i) All possible routes from A to D are :
(a) A ➝ G ➝ F ➝ E ➝ D
(b) A ➝ G ➝ D
(c) A ➝ B ➝ C ➝ D
(d) A ➝ B ➝ D

(ii) Distance between E and C are
(a) Route 1: E ➝ D ➝ C
Distance: 120 m + 200 m = 320 m.
(b) Route 2: E ➝ D ➝ B ➝ C
Distance = 120 + 100 m + 120 m
= 340 m.
∴ Shortest distance is 320 m.

(iii) All possible routes between B and F are :
(a) Route 1: B ➝ A ➝ G ➝ F
Distance = 250 m + 100 m + 150 m = 600 m.

(b) Route 2: 2 ➝ D ➝ E ➝ F
Distance = 100 m + 120 m + 300 m
= 520 m.

(c) Route 3: B ➝ D ➝ G ➝ F
Distance = 100 m + 200 m + 150 m
= 450 m.

(d) Route 4: B ➝ C ➝ D ➝ E ➝ F
Distance = 120 m + 200 m + 120 m + 300 m
= 740 m.
We find that Route 3 is shortest.
ie B ➝ D ➝ G ➝ F is the shortest route.