Samacheer Kalvi 8th Maths Solutions Term 3 Chapter 3 Geometry Additional Questions
Samacheer Kalvi 8th Maths Solutions Term 3 Chapter 3 Geometry Additional Questions
Tamilnadu Samacheer Kalvi 8th Maths Solutions Term 3 Chapter 3 Geometry Additional Questions
Question 1.
In ΔPQR, PS is a median. If QS = 7 cm find the length of QR?
Solution:
PS is the median ⇒ S is the midpoint of QR
Given
QS = 7 cm
∴ SR = 7 cm
QR = QS + SR
= 7 + 7 = 14cm
Question 2.
In ΔABC, G is the centroid. If AD = 6 cm, BC = 4 cm and BE = 9 cm find the perimeter of ΔBDG.
Solution:
In ΔABC, G is the centroid.
If AD = 6 cm
⇒ GD = 1/3 of AD = 1/3 (6)
BE = 9 cm
⇒ BG = 2/3 of BE = 2/3 (9) = 6cm
Also D is the midpoint of BC ⇒ BD
= 1/1 of BC = 1/2 (4) = 2cm
∴ Perimeter of ΔBDG = BD + GD + BG = 2 + 2 + 6 = 10 cm
Question 3.
Construct a rhombus FISH with FS = 8 cm and ∠F = 80°
Solution:
Given FS = 8 cm and ∠F = 80°
Steps :
(i) Drawn a line segment FS = 7 cm.
(ii) At F, made ∠SFX = ∠SFY = 40° on either side of FS.
(iii) At S, made ∠FSP = ∠FSQ = 40° on either side of FS
(iv) Let FX and SP cut at H and FY and SQ cut at I.
(v) FISH is the required rhombus
Calculation of Area:
Area of the rhombus FISH = 1/2 × d1 × d2 sq.units = 1/2 × 5.9 × 7 cm² = 20.65 cm²
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