Samacheer Kalvi 9th Maths Solutions Chapter 3 Algebra Ex 3.2

Samacheer Kalvi 9th Maths Solutions Chapter 3 Algebra Ex 3.2

Tamilnadu Samacheer Kalvi 9th Maths Solutions Chapter 3 Algebra Ex 3.2

9th Maths Algebra Exercise 3.2 Question 1.
Find the value of the polynomial f(y) = 6y – 3y² + 3 at (i) y = 1 (ii) y = -1 (iii) y = 0
Solution:
(i) At y = 1,
f(1) = 6(1) – 3(1)² + 3 = 6 – 3 + 3 = 6
(ii) At y = -1,
f(-1) = 6(-1) – 3(-1)² + 3 = -6 – 3 + 3 = -6
(iii) At y = 0,
f(0) = 6(0) – 3(0)² + 3 = 0 – 0 + 3 = 3

9th Maths Exercise 3.2 Question 2.

Ex 3.2 Class 9 Algebra Question 3.

Find the zeros of the polynomial in each of the following :
(i) p(x) = x – 3
(ii) p(x) = 2x + 5
(iii) q(y) = 2y – 3,
(iv) f(z) = 8z
(v) p(x) = ax where a ≠ 0,
(vi) h(x) = ax + b, a ≠ 0, a, b ∈ R
Solution:
(i) x = 3.
p( 3) = 3 – 3 = 0
∴ The zero of the polynomial is x = 3.

(iv) f(z) = 8z,
If 8z = 0
z = 0/8 = 0
f(0) = 8(0) = 0
∴ z = 0 is the zero of the given polynomial.

Class 9 Maths Exercise 3.2 Solutions Question 4.

(iv) 9x – 4 = 0
9x = 4
∴ x = 4/9

Algebra 3.2 Answers Question 5.

Samacheer Kalvi 9th Standard Maths Question 6.

Find the number of zeros of the following polynomial represented by their graphs.

Solution:
(i) The curve cuts the x-axis at two points. ∴ The equation has 2 zeros.
(ii) Since the curve cuts the x-axis at 3 different points. The number of zeros of the given curve is three.
(iii) Since the curve doesn’t cut the x axis. The number of zeros of the given curve is zero.
(iv) The curve cut the x-axis at one point. ∴ The equation has one zero.
(v) The curve cut the x axis at one point. ∴ The equation has one zero.