TN 9 Maths

Samacheer Kalvi 9th Maths Solutions Chapter 5 Coordinate Geometry Ex 5.4

Samacheer Kalvi 9th Maths Solutions Chapter 5 Coordinate Geometry Ex 5.4

Tamilnadu Samacheer Kalvi 9th Maths Solutions Chapter 5 Coordinate Geometry Ex 5.4

Question 1.
Find the coordinates of the point which divides the line segment joining the points
A (4, -3) and B (9, 7) in the ratio 3 : 2.
Solution:

Question 2.
In what ratio does the point P (2, -5) divide the line segment joining A (-3, 5) and B (4, -9).
Solution:

Question 3.
Find the coordinates of a point P on the line segment joining A(1, 2) and B (6, 7) in such a way that AP = 25AB.
Solution:

Question 4.
Find the coordinates of the points of trisection of the line segment joining the points A (-5, 6) and B (4, -3).
Solution:

Samacheer Kalvi 9th Maths Chapter 5 Coordinate Geometry Ex 5.4 5

 

Question 5.
The line segment joining A(6, 3) and B(-1, -4) is doubled in length by adding half of AB to each end. Find the coordinates of the new end points.
Solution:

Samacheer Kalvi 9th Maths Chapter 5 Coordinate Geometry Ex 5.4 7
Similarly by Mid point of DM = A(6, 3)
Samacheer Kalvi 9th Maths Chapter 5 Coordinate Geometry Ex 5.4 50

Question 6.
Using section formula, show that the points A(7, -5), B(9, -3) and C(13, 1) are collinear.
Solution:


∴ AB + BC = AC, Here B is the common Point. ∴ A, B, C are collinear

 

Question 7.
A line segment AB is increased along its length by 25% by producing it to C on the side of B. If A and B have the coordinates(-2, -3) and (2, 1) respectively, then find the coordinates of C.
Solution:

P is at 25% distance from B on its left and C is at 25% distance from B on its right.
∴ B is the mid point of PC

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