KSEEB Solutions for Class 8 Maths Chapter 9 Commercial Arithmetic Ex 9.2

KSEEB Solutions for Class 8 Maths Chapter 9 Commercial Arithmetic Ex 9.2

Karnataka Board Class 8 Maths Chapter 9 Commercial Arithmetic Ex 9.2

Question 1.
Sonu bought a bicycle for Rs. 3750 and spent Rs. 250 on its repairs. He sold it for Rs. 4400. Find his loss or profit percentage.
Answer:
C.P = 3750 + 250 = Rs. 4000 S P = Rs. 4400
S.P > C.P
∴ S.P – C.P = 4400 – 4000 = Rs. 400
Protit percent =  × 100
=  × 100 = 10
Profit percent = 10%

Question 2.
A shop keeper purchases an article for Rs. 3500 and pays the transport charge of Rs. 100. He incurred a loss of 12% in selling this. Find selling price of the article.
Answer:
C.P = 3500 + 100 = Rs. 3600
Loss percent = 12%

S.P = Rs.3168.

Question 5.
A storekeeper sells a book at a 15% gain. Had he sold it for Rs. 18 more. He would have gained 18%. Find the cost price of the book.
Answer:
Let the C.P be Rs. x
gain % = 15%

Had he sold it for Rs. 18 more the new S.P.
would be Rs. 115x/100 . This is equal to S.P
When the gain percent is 18%
S.P when gain percent is 18% is

118 x – 115 x = 1800
3 x = 1800
x = 1800/3
x = 600
∴ Cost price = Rs.600.

Question 6.
The cost price of 12 pens is equal to the selling price of 10 pens. Find the profit percentage.
Answer:
Let the C.P of one pen be Rs. 1
∴ C.P of 12 pens = Rs. 12
Given S.P. of 10 pens = C.P. of 12 pens.
S.P. of 10 pens = Rs. 12 C.P of 10 pens = Rs. 10
∴ S.P > C.P So there is gain
Gain = S.P – C.P= 12 – 10 = 2
Gain percent = Gain/C.P × 100
= 2/10 × 100 = 20 %
Gain percent = 20%