KSEEB Solutions for Class 7 Maths Chapter 6 The Triangles and Its Properties Ex 6.2
KSEEB Solutions for Class 7 Maths Chapter 6 The Triangles and Its Properties Ex 6.2
Karnataka State Syllabus Class 7 Maths Chapter 6 The Triangles and Its Properties Ex 6.2
Question 1.
Find the value of the unknown exterior angle x in the following diagrams :
i) ∠x = 50° + 70° = 120°
(∵ The exterior angle of the triangle is equal to the sum of its two interior opposite angles.)
ii) ∠x = 45° + 65° = 110°
(∵ The exterior angle of the triangle is equal to the sum of its two interior opposite angles.)
iii) ∠x = 30° + 40° = 70°
(∵ The exterior angle of the triangle is equal to the sum of its two interior opposite angles.)
iv) ∠x = 60° + 60° = 120°
(∵ The exterior angle of the triangle is equal to the sum of its two interior opposite angles.)
v) ∠x = 50° + 50° = 100°
(∵ The exterior angle of a triangle is equal to the sum of its two interior opposite angles.)
Question 2.
Find the value of the unknown interior angle x in the following figures:
Solution:
i) ∠x + 50° = 115°
∵ The exterior angle of a triangle is equal to the sum of its two interior opposite angles.
∵ ∠x = 115° – 50° = 65°
ii) ∠x + 70° = 100°
Solution:
(∵ The exterior angle of a triangle is equal to the sum of its two interior opposite angles)
∴ ∠x = 100° – 70°= 30°
iii) ∠x + 90° = 125°
∵ The exterior angle of a triangle is equal to the sum of its two interior opposite angles.
∴ ∠x = 125° – 90° = 35°
iv) ∠x + 60° = 120°
∵ The exterior angle of a triangle is equal to the sum of its two interior opposite angles.
∠x = 120° – 60° = 6o°
v) ∠x + 30° = 80°
∵ The exterior angle of a triangle is equal to the sum of its two interior opposite angles.
∵ ∠x = 80° – 30° = 50°
vi) ∠x + 35° = 75°
∵ The exterior angle of a triangle is equal to the sum of its two interior opposite angles.
∴ ∠x = 75° – 35° = 40°
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